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If x = a cos t and y = b sin t, then find d2ydx2. - Mathematics

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प्रश्न

If x = a cos t and y = b sin t, then find `(d^2y)/(dx^2)`.

योग
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उत्तर

If x = a cos t, y = b sin t

`dx/(dt)` = – a sin t

`dy/(dt)` = b cos t

`dy/dx = (dy/(dt))/(dx/(dt))`

= `(b cos t)/(-a sin t)`

= `(-b)/a cot t`

`(d^2y)/(dx^2) = b/a "cosec"^2t xx (dt)/dx`

= `b/a "cosec"^2t xx (-1)/(a sin t)`

= `-b/a^2 "cosec"^3t`.

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2022-2023 (March) Delhi Set 3

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