हिंदी

The derivative of cos–1(2x2 – 1) w.r.t. cos–1x is ______. - Mathematics

Advertisements
Advertisements

प्रश्न

The derivative of cos–1(2x2 – 1) w.r.t. cos–1x is ______.

विकल्प

  • 2

  • `(-1)/(2sqrt(1 - x^2)`

  • `2/x`

  • 1 – x2 

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

The derivative of cos–1(2x2 – 1) w.r.t. cos–1x is 2.

Explanation:

Let y = cos–1(2x2 – 1) and t = cos–1x

Differentiating both the functions w.r.t. x

`"dy"/"dx" = "d"/"dx" cos^-1 (2x^2 - 1)` and `"dt"/"dx" = "d"/"dx" cos^-1x`

⇒ `"dy"/"dx" = (-1)/sqrt(1 - (2x^2 - 1)^2) * "d"/"dx" (2x^2 - 1)` and `"dt"/"dx" = (-1)/sqrt(1 - x^2)`

= `(-1.4x)/sqrt(1 - (4x^4 + 1 - 4x^2)` and `"dt"/"dx" = (-1)/sqrt(1 - x^2)`

= `(-4x)/sqrt(1 - 4x^4 - 1 + 4x^2)`

= `(-4x)/sqrt(4x^2 - 4x^4)`

= `(-4x)/(2xsqrt(1 - x^2)`

⇒ `"dy"/"dx" = (-2)/sqrt(1 - x^2)`

Now `"dy"/"dx" = ("dy"/"dx")/("dt"/"dx")`

= `((-2)/sqrt(1 - x^2))/((-1)/sqrt(1 - x^2))`

= 2.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Continuity And Differentiability - Exercise [पृष्ठ ११५]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 12
अध्याय 5 Continuity And Differentiability
Exercise | Q 93 | पृष्ठ ११५

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

If x cos(a+y)= cosy then prove that `dy/dx=(cos^2(a+y)/sina)`

Hence show that `sina(d^2y)/(dx^2)+sin2(a+y)(dy)/dx=0`


Find the second order derivative of the function.

x20


Find the second order derivative of the function.

e6x cos 3x


Find the second order derivative of the function.

tan–1 x


Find the second order derivative of the function.

sin (log x)


If y = 5 cos x – 3 sin x, prove that `(d^2y)/(dx^2) + y = 0`.


If y = cos–1 x, find `(d^2y)/dx^2` in terms of y alone.


If y = 3 cos (log x) + 4 sin (log x), show that x2y2 + xy1 + y = 0.


If y = 500e7x + 600e–7x, show that `(d^2y)/(dx^2)` = 49y.


If x7 . y9 = (x + y)16 then show that `"dy"/"dx" = "y"/"x"`


If `x^3y^5 = (x + y)^8` , then show that `(dy)/(dx) = y/x`


Find `("d"^2"y")/"dx"^2`, if y = `"x"^-7`


Find `("d"^2"y")/"dx"^2`, if y = log (x).


Find `("d"^2"y")/"dx"^2`, if y = `"x"^2 * "e"^"x"`


sec(x + y) = xy


If ax2 + 2hxy + by2 + 2gx + 2fy + c = 0, then show that `"dy"/"dx" * "dx"/"dy"` = 1 


If x sin (a + y) + sin a cos (a + y) = 0, prove that `"dy"/"dx" = (sin^2("a" + y))/sin"a"`


If y = tan–1x, find `("d"^2y)/("dx"^2)` in terms of y alone.


Let for i = 1, 2, 3, pi(x) be a polynomial of degree 2 in x, p'i(x) and p''i(x) be the first and second order derivatives of pi(x) respectively. Let,

A(x) = `[(p_1(x), p_1^'(x), p_1^('')(x)),(p_2(x), p_2^'(x), p_2^('')(x)),(p_3(x), p_3^'(x), p_3^('')(x))]`

and B(x) = [A(x)]T A(x). Then determinant of B(x) ______


If y = `sqrt(ax + b)`, prove that `y((d^2y)/dx^2) + (dy/dx)^2` = 0.


If y = tan x + sec x then prove that `(d^2y)/(dx^2) = cosx/(1 - sinx)^2`.


Read the following passage and answer the questions given below:

The relation between the height of the plant ('y' in cm) with respect to its exposure to the sunlight is governed by the following equation y = `4x - 1/2 x^2`, where 'x' is the number of days exposed to the sunlight, for x ≤ 3.

  1. Find the rate of growth of the plant with respect to the number of days exposed to the sunlight.
  2. Does the rate of growth of the plant increase or decrease in the first three days? What will be the height of the plant after 2 days?

`"Find"  (d^2y)/(dx^2)  "if"  y=e^((2x+1))`


Find `(d^2y)/dx^2 if, y = e^((2x + 1))`


Find `(d^2y)/dx^2` if, `y = e^((2x + 1))`


Find `(d^2y)/dx^2` if, `y = e^((2x + 1))`


Find `(d^2y)/(dx^2)` if, y = `e^((2x+1))`


Find `(d^2y)/dx^2` if, `y = e^((2x + 1))`


Find `(d^2y)/dx^2` if, y = `e^(2x +1)`


If y = 3 cos(log x) + 4 sin(log x), show that `x^2 (d^2y)/(dx^2) + x dy/dx + y = 0`


Find `(d^2y)/dx^2` if, `y = e^((2x+1))`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×