हिंदी

If y = tan x + sec x then prove that d2ydx2=cosx(1-sinx)2.

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प्रश्न

If y = tan x + sec x then prove that `(d^2y)/(dx^2) = cosx/(1 - sinx)^2`.

योग
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उत्तर

y = tan x + sec x

`dy/dx = d/dx (tan x) + d/dx (sec x)`

= sec2 x + sec x tan x

= sec x (sec x + tan x)

= `1/cosx(1/cosx + sinx/cosx)`

= `(1 + sinx)/(cos^2x)`

`dy/dx = (1 + sinx)/(1 - sin^2x)`

= `1/(1 - sinx)`

`(d^2y)/(dx^2) = ((1 - sinx)0 - 1(-cosx))/(1 - sinx)^2`

= `cosx/(1 - sinx)^2`.

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2022-2023 (March) Delhi Set 1

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