हिंदी

If y = tan–1x, find ddxd2ydx2 in terms of y alone.

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प्रश्न

If y = tan–1x, find `("d"^2y)/("dx"^2)` in terms of y alone.

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उत्तर

Given that: y = tan–1x

⇒ x = tan y

Differentiating both sides w.r.t. y

`"dx"/"dy"` = sec2y

⇒ `"dy"/'dx" = 1/(sec^2y)` = cos2y

Again differentiating both sides w.r.t. x

⇒ `"d"/"dx"("dy"/"dx") = "d"/"dx"(cos^2y)`

⇒ `("d"^2y)/("dx"^2) = 2cos y * "d"/"dx" (cos y)`

⇒ `("d"^2y)/("dx"^2) = 2cos y(- siny) * "dy"/"dx"` 

⇒ `("d"^2y)/("dx"^2) = - 2sin y cos y * cos^2 y`

∴ `("d"^2y)/("dx"^2)` = – 2 sin y cos3y

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अध्याय 5: Continuity And Differentiability - Exercise [पृष्ठ १११]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 5 Continuity And Differentiability
Exercise | Q 64 | पृष्ठ १११

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