Advertisements
Advertisements
प्रश्न
If three angles of a quadrilateral are 90° each, show that the given quadrilateral is a rectangle.
Advertisements
उत्तर
The given quadrilateral ABCD will be a rectangle, if its each angle is 90°
Since, the sum of interior angles of a quadrilateral is 360°.
∴∠A +∠B + ∠C + ∠D = 360°
⇒ 90° + 90° + 90° + ∠D = 360°
⇒ 270° + ∠D = 360°
⇒ ∠D = 360° – 270°
⇒ ∠D = 90°
Since, each angle of the quadrilateral is 90°. ∴The given quadrilateral is a rectangle.
APPEARS IN
संबंधित प्रश्न
Given here are some figures:
 |
 |
 |
 |
 |
 |
 |
 |
Classify each of them on the basis of the following:
- Simple curve
- Simple closed curve
- Polygon
- Convex polygon
- Concave polygon
Define the following term Convex Quadrilateral .
In Fig. 16.21, the bisectors of ∠A and ∠B meet at a point P. If ∠C = 100° and ∠D = 50°, find the measure of ∠APB.
In ΔABC, E is the mid-point of median AD such that BE produced meets AC at F. IF AC = 10.5 cm, then AF =
Three angles of a quadrilateral are equal. If the fourth angle is 69°; find the measure of equal angles.
Write two conditions that will make the adjoining figure a square.
Observe the figure below and find out their name.
In the figure, PQRS and PTVS are two cyclic quadrilaterals, If ∠QRS = 100°, then ∠TVS =
In the following figure, What is AC – EC?
Using the information given, name the right angles in part of figure:
AC ⊥ CD
