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प्रश्न
If mx2 – nx + 8 has x – 2 as a factor, then ______.
विकल्प
2m – n = 4
2m + n = 4
2n + m = 4
n – 2m = 4
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उत्तर
If mx2 – nx + 8 has x – 2 as a factor, then n – 2m = 4.
Explanation:
Let f(x) = mx2 – nx + 8
Given x – 2 is a factor of f(x).
Then f(2) = 0
`\implies` m × 22 – n × 2 + 8 = 0
`\implies` 4m – 2n + 8 = 0
`\implies` 2m – n + 4 = 0
`\implies` n – 2m = 4
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