हिंदी

If in a triangle, the angles are in A.P. and b: c = 3:2, then A is equal to

Advertisements
Advertisements

प्रश्न

If in a triangle, the angles are in A.P. and b: c = `sqrt3: sqrt2`, then A is equal to

विकल्प

  • 30°

  • 60°

  • 75°

  • 45°

MCQ
Advertisements

उत्तर

If in a triangle, the angles are in A.P. and b: c = `sqrt3: sqrt2`, then A is equal to 75°.

Explanation:

`angle"B"` = 60° `angle"A"` + `angle"C"` = 120

Now,

`b/c = sqrt3/sqrt2 = sin B/sin A`

sin C = `1/sqrt2`

`angle"C"` = 45°

Hence, `angle"A"` = 75°

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Trigonometric Functions - Miscellaneous exercise 3 [पृष्ठ १०७]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 3 Trigonometric Functions
Miscellaneous exercise 3 | Q 1.10 | पृष्ठ १०७

संबंधित प्रश्न

Find the principal solution of the following equation: 

Sec θ = `(2)/sqrt(3)`


Find the principal solution of the following equation: 

tan θ = – 1


Find the general solution of the following equation:

sinθ = `1/2`.


Find the general solution of the following equation:

tan θ = `(1)/(sqrt(3))`


Find the general solution of the following equation:

tan `(2θ)/(3) = sqrt3`


State whether the following equation have solution or not?

3 tanθ = 5


In ΔABC, if ∠A = 45°, ∠B = 60° then find the ratio of its sides.


In Δ ABC, prove that a3 sin(B – C) + b3sin(C – A) + c3sin(A – B) = 0


With usual notations prove that 2(bc cosA + ac cosB + ab cosC) = a2 + b2 + c.


Select the correct option from the given alternatives:

If cos pθ = cos qθ, p ≠ q, then ______.


If `sqrt3 cos x − sin x = 1`, then general value of x is ______.


Select the correct option from the given alternatives:

In ΔABC, ac cos B - bc cos A = _______


Select the correct option from the given alternatives:

`2 "tan"^-1 (1/3) + "tan"^-1 (1/7) =` _____


Select the correct option from the given alternatives:

`"tan"(2"tan"^-1 (1/5) - pi/4)` = ______


Find the principal solutions of the following equation:

tan 3θ = - 1


With the usual notations, prove that `(sin("A" - "B"))/(sin ("A" + "B")) = ("a"^2 - "b"^2)/"c"^2`


In Δ ABC, if cos A = sin B - cos C then show that it is a right-angled triangle.


If 2 tan-1(cos x) = tan-1(2 cosec x), then find the value of x.


If tan-12x + tan-13x = `pi/4`, then find the value of x.


Show that `tan^-1  1/2 - tan^-1  1/4 = tan^-1  2/9`.


Show that `cot^-1  1/3 - tan^-1  1/3 = cot^-1  3/4`.


Show that `tan^-1  1/2 = 1/3  tan^-1  11/2`


Show that `2 cot^(-1)  3/2 +  sec^(-1)  13/12 = π/2`


Prove the following:

`cos^-1 "x" = tan^-1 (sqrt(1 - "x"^2)/"x")`, if x > 0


If | x | < 1, then prove that

`2 tan^-1 "x" = tan^-1 ("2x"/(1 - "x"^2)) = sin^-1 ("2x"/(1 + "x"^2)) = cos^-1 ((1 - "x"^2)/(1 + "x"^2))`


Find the principal solutions of sin x = `-1/2`


Find the principal solutions of tan x = `-sqrt(3)`


`cos^-1 (cos  (4pi)/3)` = ______.


`int 1/(sin x * cos x)` dx = ?


If y = sin-1 `[(sqrt(1 + x) + sqrt(1 - x))/2]`, then `"dy"/"dx"` = ?


Which of the following equations has no solution?


If function

f(x) = `x - |x|/x, x < 0`
      = `x + |x|/x, x > 0`
      = 1, x = 0, then


The value of θ in (π, 2π) satisfying the equation sin2θ - cos2θ = 1 is ______ 


Which of the following is true in a triangle ABC?


If sin θ + cos θ = 1, then the general value of θ is ______.


The general value of θ in the equation `2sqrt(3) cos theta = tan theta` is ______.


Find the principal solutions of cot θ = 0


The general solution of x(1 + y2)1/2 dx + y(1 + x2)1/2 dy = 0 is ______.


Which of the following equation has no solution?


The general solution of the equation tan2 x = 1 is ______.


The general solution of sin x – 3 sin 2x + sin 3x = cos x – 3 cos 2x + cos 3x is ______.


Find the general solution of sin θ + sin 3θ + sin 5θ = 0


If `2sin^-1  3/7` = cos–1β, then find the value of β.


If `sin^-1  4/5 + cos^-1  12/13` = sin–1α, then find the value of α.


If tan θ + sec θ = `sqrt(3)`, find the general value of θ.


If tan3θ = cotθ, then θ =


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×