हिंदी

If in the Expansion of (A + B)N and (A + B)N + 3, the Ratio of the Coefficients of Second and Third Terms, and Third and Fourth Terms Respectively Are Equal, Then N is (A) 3 (B) 4 (C) 5 (D) 6

Advertisements
Advertisements

प्रश्न

If in the expansion of (a + b)n and (a + b)n + 3, the ratio of the coefficients of second and third terms, and third and fourth terms respectively are equal, then n is

विकल्प

  • 3

  • 4

  •  5

  • 6

     
MCQ
Advertisements

उत्तर

n = 5

\[\text{ Coefficients of the 2nd and 3rd terms in } (a + b )^n \text{ are } ^{n}{}{C}_1 \text{ and }  ^{n}{}{C}_2 \]

\[\text{ Coefficients of the 3rd and 4th terms in } (a + b )^{n + 3} \text{ are } ^{n + 3}{}{C}_2 \text{ and  }^{n + 3}{}{C}_3 \]

\[\text{ Thus, we have} \]

\[\frac{^{n}{}{C}_1}{^{n}{}{C}_2} = \frac{^{n + 3}{}{C}_2}{^{n + 3}{}{C}_3}\]

\[ \Rightarrow \frac{2}{n - 1} = \frac{3}{n + 1}\]

\[ \Rightarrow 2n + 2 = 3n - 3\]

\[ \Rightarrow n = 5\]

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 18: Binomial Theorem - Exercise 18.4 [पृष्ठ ४६]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 11
अध्याय 18 Binomial Theorem
Exercise 18.4 | Q 4 | पृष्ठ ४६

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

In the expansion of (1 + a)m + n, prove that coefficients of am and an are equal.


The coefficients of the (r – 1)thrth and (r + 1)th terms in the expansion of (x + 1)n are in the ratio 1:3:5. Find n and r.


Find n, if the ratio of the fifth term from the beginning to the fifth term from the end in the expansion of `(root4 2 + 1/ root4 3)^n " is " sqrt6 : 1`


Find the middle term in the expansion of: 

(i)  \[\left( \frac{2}{3}x - \frac{3}{2x} \right)^{20}\]

 


Find the middle term in the expansion of: 

(ii)  \[\left( \frac{a}{x} + bx \right)^{12}\]

 


Find the middle term in the expansion of: 

(iv)  \[\left( \frac{x}{a} - \frac{a}{x} \right)^{10}\]

 


Find the middle terms in the expansion of: 

(iii) \[\left( 3x - \frac{2}{x^2} \right)^{15}\]

 


Find the middle terms in the expansion of:

(iv)  \[\left( x^4 - \frac{1}{x^3} \right)^{11}\]

 


Find the middle terms(s) in the expansion of:

(iv)  \[\left( 2x - \frac{x^2}{4} \right)^9\]


Find the middle terms(s) in the expansion of:

(v) \[\left( x - \frac{1}{x} \right)^{2n + 1}\]

 


Find the middle terms(s) in the expansion of: 

(vii) \[\left( 3 - \frac{x^3}{6} \right)^7\]

  


Find the middle terms(s) in the expansion of:

(x)  \[\left( \frac{x}{a} - \frac{a}{x} \right)^{10}\]

 


Find the term independent of x in the expansion of the expression:

(ii)  \[\left( 2x + \frac{1}{3 x^2} \right)^9\]

 


Find the term independent of x in the expansion of the expression: 

(v)  \[\left( \frac{\sqrt{x}}{3} + \frac{3}{2 x^2} \right)^{10}\]

 


Prove that the coefficient of (r + 1)th term in the expansion of (1 + x)n + 1 is equal to the sum of the coefficients of rth and (r + 1)th terms in the expansion of (1 + x)n.


The coefficients of 5th, 6th and 7th terms in the expansion of (1 + x)n are in A.P., find n.

 

If in the expansion of (1 + x)n, the coefficients of three consecutive terms are 56, 70 and 56, then find n and the position of the terms of these coefficients.


If in the expansion of (1 + y)n, the coefficients of 5th, 6th and 7th terms are in A.P., then nis equal to


In the expansion of \[\left( \frac{1}{2} x^{1/3} + x^{- 1/5} \right)^8\] , the term independent of x is

 

If the sum of odd numbered terms and the sum of even numbered terms in the expansion of  \[\left( x + a \right)^n\]  are A and B respectively, then the value of \[\left( x^2 - a^2 \right)^n\] is 

 

Find the middle term in the expansion of `(2ax - b/x^2)^12`.


Find the term independent of x in the expansion of `(3x - 2/x^2)^15`


Find the middle term (terms) in the expansion of `(3x - x^3/6)^9`


Find the coefficient of `1/x^17` in the expansion of `(x^4 - 1/x^3)^15`


If xp occurs in the expansion of `(x^2 + 1/x)^(2n)`, prove that its coefficient is `(2n!)/(((4n - p)/3)!((2n + p)/3)!)`


In the expansion of `(x^2 - 1/x^2)^16`, the value of constant term is ______.


The coefficient of x256 in the expansion of (1 – x)101(x2 + x + 1)100 is ______.


The middle term in the expansion of (1 – 3x + 3x2 – x3)6 is ______.


Let the coefficients of the middle terms in the expansion of `(1/sqrt(6) + βx)^4, (1 - 3βx)^2` and `(1 - β/2x)^6, β > 0`, common difference of this A.P., then `50 - (2d)/β^2` is equal to ______.


The sum of the real values of x for which the middle term in the binomial expansion of `(x^3/3 + 3/x)^8` equals 5670 is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×