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If → a , → B , → C Are Mutually Perpendicular, Show that → C × ( → a × → B ) = 0 is the Converse True? - Physics

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प्रश्न

If \[\vec{A} , \vec{B} , \vec{C}\] are mutually perpendicular, show that  \[\vec{C} \times \left( \vec{A} \times \vec{B} \right) = 0\] Is the converse true?

योग
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उत्तर

Given: \[\vec{A} , \vec{B} \text{ and }\vec{C}\] are mutually perpendicular. \[\vec{A} \times \vec{B}\] is a vector with its direction perpendicular to the plane containing \[\vec{A} \text{ and } \vec{B}\]
  

∴ The angle between \[\vec{C} \text{ and } \vec{A} \times \vec{B}\] is either 0° or 180°.
i.e., \[\vec{C} \times \left( \vec{A} \times \vec{B} \right) = 0\] However, the converse is not true. For example, if two of the vectors are parallel, then also, \[\vec{C} \times \left( \vec{A} \times \vec{B} \right) = 0\] 

So, they need not be mutually perpendicular.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Physics and Mathematics - Exercise [पृष्ठ २९]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 2 Physics and Mathematics
Exercise | Q 16 | पृष्ठ २९

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