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प्रश्न
If 1 is a zero of the quadratic polynomial ax2 – 3(a – 1)x – 1 is 1, then find the value of a.
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उत्तर
Given: x = 1 is one zero of the polynomial ax2 – 3(a – 1)x – 1
Therefore, it will satisfy the above polynomial.
Now, we have
a(1)2 – (a – 1)1 – 1 = 0
⇒ a – 3a + 3 – 1 = 0
⇒ –2a = –2
⇒ a = 1
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