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प्रश्न
(i) What is observed when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube?
(ii) What type of reaction is this?
(iii) Write a balanced chemical equation to represent the above reaction.
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उत्तर
i) When a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube, the precipitation of a yellowish solid is observed. This yellowish solid is lead iodide. Potassium nitrate is formed along with lead iodide.
(ii) This is a double displacement reaction.
(iii) The balanced chemical equation for the above reaction is:
2KI(aq) + Pb(NO3)2(aq) —→ 2KNO3(aq) + PbI2(s)↓
Potassium Lead Potassium Lead
iodide nitrate nitrate iodide
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संबंधित प्रश्न
When the substance ‘A’ is added to a solution of BaSO4, a yellow precipitate is formed.
- What do you think substance A is likely to be?
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\[\ce{Potassium bromide (aq) + Barium iodide (aq) -> Potassium iodide (aq) + Barium bromide (s)}\]
What is meant by a double displacement reaction? Explain with the help of one example.
What happens when silver nitrate solution is added to sodium chloride solution?
Name the type of reaction involved.
- What happens when an aqueous solution of sodium sulphate reacts with an aqueous solution of barium chloride?
- Write the balanced chemical equation for the reaction which takes place.
- State the physical conditions of reactants in which the reaction will not take place.
- Name the type of chemical reaction which occurs.
- Give one example of another reaction which is of the same type as the above reaction.
Explain the following type of chemical reaction, giving two examples for it:
Double displacement reaction
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a. which precipitate is formed?
b. name the type of reaction.
c. write the chemical equation.
Which of the following represents a precipitation reaction?
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(i) Displacement reaction
(ii) Precipitation reaction
(iii) Combination reaction
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In a double displacement reaction ______.
