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How will you represent first order reactions graphically. - Chemistry

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प्रश्न

How will you represent first order reactions graphically.

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उत्तर

i. The differential rate law for the first-order reaction A → P is  

The equation is of the form y = mx + c. A plot of rate versus [A]t is a straight line passing through the origin. The slope of straight line = k.

Variation of rate with [A]

ii. The integrated rate law is

k = `2.303/t log_10  ["A"]_0/["A"]_"t"`

On rearrangement, the equation becomes

`(kt)/2.303 = log_10 ["A"]_0 - log_10 ["A"]_"t"`

Hence, 

The equation is of the straight line. A graph of `log_10[A]_t` versus t yields a straight line with slope `-"k"/2.303` and y-axis intercepts as log10[A]0.

Variation of `log_10 [A]_t` with time

iii. Rearranging the integrated rate law equation, we get

The equation has a straight-line form y = mx. Hence, the graph of `log_10  ([A]_0)/([A]_t)` versus t is a straight line passing through the origin.

Variation of `log_10  ([A]_0)/([A]_t)` with time
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अध्याय 6: Chemical Kinetics - Exercises [पृष्ठ १३७]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 6 Chemical Kinetics
Exercises | Q 3. xi. | पृष्ठ १३७

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