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Answer the following in brief. Derive the integrated rate law for the first-order reaction, AX(g)⟶BX(g)+CX(g) in terms of pressure.

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प्रश्न

Answer the following in brief.

Derive the integrated rate law for the first-order reaction,

\[\ce{A_{(g)} -> B_{(g)} + C_{(g)}}\] in terms of pressure.

संक्षेप में उत्तर
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उत्तर

i. For the gas phase reaction,

\[\ce{A_{(g)} -> B_{(g)} + C_{(g)}}\]

Let initial pressure of A be Pi that decreases by x within time t.

ii. Pressure of reactant A at time t

PA = Pi - x  ....(1)

The pressures of the products B and C at time t

PB = PC = x

iii. The total pressure at time t is then

P = Pi - x + x + x = Pi + x

Hence, x = P - Pi …(2)

The pressure of A at time t is obtained by substitution of Eq. (1) into Eq. (2).

Thus

PA = Pi - (P - Pi) = Pi - P + Pi = 2Pi - P

iv. The integrated rate law turns out to be

k = `2.303/"t"  "log"_10 ["A"]_0/["A"]_"t"`

The concentration is now expressed in terms of pressures.

Thus, [A]0 = Pi and [A]t = PA = 2Pi - P

Substitution gives in above

`"k" = 2.303/"t" "log"_10  "P"_"i"/(2"P"_"i" - "P")`  ...(3)

P is the total pressure of the reaction mixture at time t.

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अध्याय 6: Chemical Kinetics - Exercises [पृष्ठ १३७]

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बालभारती Chemistry [English] Standard 12 Maharashtra State Board
अध्याय 6 Chemical Kinetics
Exercises | Q 3. xii. | पृष्ठ १३७

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