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How Will You Convert the Following in Not More than Two Steps: Benzoic Acid to Benzaldehyde - Chemistry

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प्रश्न

How will you convert the following in not more than two steps:

Benzoic acid to Benzaldehyde

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उत्तर

Benzoic acid to Benzaldehyde

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2016-2017 (March) All India Set 3

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Derive van’t Hoff general solution equation.


19.5 g of CH2FCOOH is dissolved in 500 g of water. The depression in the freezing point of water observed is 1.0°C. Calculate the van’t Hoff factor and dissociation constant of fluoroacetic acid.


Give reasons for the following

Elevation of the boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.


The Van't Hoff factor (i) for a dilute aqueous solution of the strong elecrolyte barium hydroxide is (NEET) ______.


Van’t Hoff factor i is given by the expression:

(i)  i = `"Normal molar mass"/"Abnormal molar mass"`

(ii)  i = `"Abnormal molar mass"/"Normal molar mass"`

(iii) i = `"Observed colligative property"/"Calculated colligative property"`

(iv) i =  `"Calculated colligative property"/"Observed colligative property"`


Van't Hoff factor I is given by expression.


Geraniol, a volatile organic compound, is a component of rose oil. The density of the vapour is 0.46 g L–1 at 257°C and 100 mm Hg. The molar mass of geraniol is ______ g mol–1. (Nearest Integer)

[Given: R = 0.082 L atm K–1 mol–1]


When 9.45 g of ClCH2COOH is added to 500 mL of water, its freezing point drops by 0.5°C. The dissociation constant of ClCH2COOH is x × 10−3. The value of x is ______. (Rounded-off to the nearest integer)

[\[\ce{K_{f(H_2O)}}\] = 1.86 K kg mol−1]


A storage battery contains a solution of H2SO4 38% by weight. At this concentration, Van't Hoff Factor is 2.50. At the battery content freeze temperature will be ______ K.

(Kf = 1.86 K Kg mol−1)


A molecule M associates in a given solvent according to the equation \[\ce{M <=> (M)_n}\]. For a certain concentration of M, the van't Hoff factor was found to be 0.9 and the fraction of associated molecules was 0.2. The value of n is ______.


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