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प्रश्न
Calculate Van't Hoff factor for an aqueous solution of K3 [Fe(CN)6] if the degree of dissociation (α) is 0.852. What will be boiling point of this solution if its concentration is 1 molal? (Kb = 0.52 K kg/mol)
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उत्तर
K3 [Fe(CN)6] gives 4 ions in aqueous solution
i = 1 + (n - 1) α
i = 1 + (4 - 1) × 0.852
i = 3.556
ΔTb = iKb m
= 3.556 × 0.52 × 1
= 1.85
Tb = 101.85°C
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संबंधित प्रश्न
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