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प्रश्न
How will the action of dilute hydrochloric acid on sodium carbonate and sodium sulphite enables you to distinguish between these two compounds?
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उत्तर
Sodium carbonate + hydrochloric acid = sodium chloride + water + carbon dioxide
\[\ce{NaCO3 + HCl -> NaCl + H2O + CO2}\]
Sodium sulphite + hydrochloric acid -> sodium chloride + water + hydrogen sulphide
\[\ce{2Na2SO3+ 4HCI -> 4NaCI + 6H2O + 2H2S}\]
Production of Foul smelling hydrogen sulphide gas will easily help to distinguish between sodium carbonate and sodium sulphite.
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संबंधित प्रश्न
Match the salts given in Column I with their method of preparation given in Column II.
| Column I | Column II | ||
| 1 | Pb(NO3)2 from PbO | A | Simple displacement |
| 2 | MgCl2 from Mg | B | Titration |
| 3 | FeCl3 from Fe | C | Neutralization |
| 4 | NaNO3 from NaOH | D | Precipitation |
| 5 | ZnCO3 from ZnSO4 | E | Combination |
You are given a mixture of precipitated copper hydroxide and zinc hydroxide. Name a solvent which will dissolve:
Only copper hydroxide
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| Aqueous salt Solution | Colour of Participitate when NaOH is added in a samll quantity | Nature of precipitate(soluble or insoluble) when NaOH added in excess |
| Copper (II) Solution | ||
| Zinc nitrate | ||
| Lead nitrate | ||
| Calcium chloride | ||
| Iron(III) sulphate |
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\[\ce{CuSO4 ->[A]Cu(OH)2 ->[B] [Cu(NH3)4]SO4}\]
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The hydroxide soluble in excess of ammonium hydroxide is ______.
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Write balanced equation for a coloured metallic oxide which dissolves in alkalis to yield colourless solutions.
