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प्रश्न
How much should the pressure on a litre of water be changed to compress it by 0.10%?
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उत्तर १
Volume of water, V = 1 L
It is given that water is to be compressed by 0.10%.
:.Fractional change, `(triangle V)/V = 0.1/100 xx 1 = 10^(-3)`
`"Bulk modulus", B = rho/((triangle V)/V)`
`p= B xx (triangle V)/V`
Bulk modulus of water, `B = 2.2 xx 10^9 Nm^(-2)`
`p = 2.2 xx 10^(9) xx 10^(-3)`
`= 2.2 xx 10^6 Nm^(-2)`
Therefore, the pressure on water should be 2.2 ×106 Nm–2.
उत्तर २
Here `V = 1 "litre" = 10^(-3) m^3; ("ΔV/V") = 0.10/100 = 10^(-3)`
`K = (pV)/(triangle V)`
or `p = k (triangle V)/V = (2.2 xx 10^9) xx 10^(-3) = 2.2 xx 10^6 Pa`
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