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How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed?

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प्रश्न

How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed?

योग
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उत्तर

There will be as many ways as there are ways of filling 3 vacant    places in succession with the five given digits.

In succession by the given five digits. In this case, repetition of digits is allowed. Therefore, the unit place can be filled in by any of the given five digits. Similarly, tens and hundreds digits can be filled in by any of the given five digits.

Thus, by the multiplication principle, the number of ways in which three-digit numbers can be formed from the given digits is 5 × 5 × 5 = 125.

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अध्याय 6: Permutations and Combinations - EXERCISE 6.1 [पृष्ठ १०४]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 6 Permutations and Combinations
EXERCISE 6.1 | Q 1. (i) | पृष्ठ १०४

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