Advertisements
Advertisements
प्रश्न
Give a reason for HF is a polar molecule
Advertisements
उत्तर
- When a covalent bond is formed between two atoms of different elements that have different electronegativities, the shared electron pair does not remain at the centre. The electron pair is pulled towards the more electronegative atom resulting in the separation of charges.
- In H-F, fluorine is more electronegative than hydrogen. Therefore, the shared electron pair is pulled towards fluorine and fluorine acquires partial −ve charge and simultaneously hydrogen acquires partial +ve charge. This gives rise to dipole and the H-F bond becomes polar. Hence, H-F is a polar molecule.
APPEARS IN
संबंधित प्रश्न
Select and write the most appropriate alternatives from the given choices.
The angle between the two covalent bonds is minimum in:
In Ammonia molecule the bond angle is 107° and in water molecule it is 104°35', although in both the central atoms are sp3 hybridized Explain.
Which type of hybridization is present in the ammonia molecule?
Write the geometry and bond angle present in ammonia.
F-Be-F is a liner molecule but H-O-H is angular. Explain.
In the case of bond formation in Acetylene molecule: State number of sigma and pi bonds formed.
In the case of bond formation in Acetylene molecule: Name the type of Hybridization.
Define Bond Length
Using data from the Table, answer the following:
| Examples | C2H6 Ethane | C2H4 Ethene | C2H2 Ethyne |
| Structure |
\[\begin{array}{cc} \backslash \phantom{......}/\phantom{.}\\ \ce{—C – C —}\\ /\phantom{......}\backslash\phantom{.}\end{array}\] |
\[\begin{array}{cc} \backslash \phantom{......}/\\ \ce{C \text{=} C}\\ /\phantom{......}\backslash\end{array}\] |
\[\ce{- C ≡ C -}\] |
| Type of bond between carbons | single | double | triple |
| Bond length (nm) | 0.154 | 0.134 | 0.120 |
| Bond Enthalpy kJ mol-1 | 348 | 612 | 837 |
- What happens to the bond length when unsaturation increases?
- Which is the most stable compound?
- Indicate the relationship between bond strength and Bond enthalpy.
- Comment on the overall relation between Bond length, Bond Enthalpy, and Bond strength and stability.
Complete the flow chart.
| Molecular Formula | Structural Formula | Shape/ Geometry | Bond angle |
| BeCl2 | 180° | ||
| O=C=O | Linear | ||
| C2H2 |
Write the formula to calculate the bond order of molecule.
Energy required to dissociate 6 g of gaseous hydrogen into free gaseous atoms is 208 kcal at 25°C. Bond energy of H-H bond will be ____________.
In gas phase H-O-O-H bond angle in H2O2 is ______.
What is the value of C-O-H bond angle in CH3_OH?
Which of following bonds has maximum bond length?
Consider the reactions.
\[\ce{C_{(s)} + 2H2_{(g)} -> CH4_{(g)}}\], ΔH = −x kcal
\[\ce{C_{(g)} + 4H_{(g)} -> CH4_{(g)}}\], ΔH = −x1 kcal
\[\ce{CH4_{(g)} -> CH3_{(g)} + H_{(g)}}\], ΔH = +y kcal
The average C-H bond enthalpy is:
Which of the following pairs have identical bond order?
The bond angle is minimum in ____________.
Identify the CORRECT option.
Which of the following is INCORRECTLY matched?
What is the bond order of B2 molecule?
Why is bond order of Be2 molecule zero?
(Nb = bonding electrons, Na = antibonding electrons)
