हिंदी

Write the formula to calculate the bond order of molecule.

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प्रश्न

Write the formula to calculate the bond order of molecule.

एक पंक्ति में उत्तर
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उत्तर

Bond order of a molecule = `("N"_"b"-"N"_"a")/2`

where Nb is the number of electrons present in bonding MOs and Na is the number of electrons present in antibonding MOs.

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अध्याय 5: Chemical Bonding - Exercises [पृष्ठ ८०]

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बालभारती Chemistry [English] Standard 11 Maharashtra State Board
अध्याय 5 Chemical Bonding
Exercises | Q 7. (H) | पृष्ठ ८०

संबंधित प्रश्न

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Examples C2H6 Ethane C2H4 Ethene C2H2 Ethyne
Structure

\[\begin{array}{cc} \backslash \phantom{......}/\phantom{.}\\ \ce{—C – C —}\\  /\phantom{......}\backslash\phantom{.}\end{array}\]

\[\begin{array}{cc} \backslash \phantom{......}/\\ \ce{C \text{=} C}\\  /\phantom{......}\backslash\end{array}\]

\[\ce{- C ≡ C -}\]
Type of bond between carbons single double triple
Bond length (nm) 0.154 0.134 0.120
Bond Enthalpy kJ mol-1 348 612 837
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\[\ce{C_{(s)} + 2H2_{(g)} -> CH4_{(g)}}\], ΔH = −x kcal

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(Nb = bonding electrons, Na = antibonding electrons)


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