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प्रश्न
For a chemical reaction R → P, the variation in the concentration (R) vs. time (t) plot is given as:
(i) Predict the order of the reaction.
(ii) What is the slope of the curve?
(iii) Write the unit of rate constant for this reaction.
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उत्तर १
For a chemical reaction R→P, the variation in the concentration (R) vs. time (t) plot is given as follows:
(i) The order of the reaction zero.
(ii) Slope = -k
उत्तर २
(i) Predict the order of the reaction
The graph shows a straight line when concentration of reactant R is plotted against time t.
[R] = [R]0 − kt
Since the plot is a straight line with a negative slope, the reaction is zero order.
(ii) Slope of the curve
From the zero-order equation:
[R] = [R]0 − kt
The slope of the [R] vs t graph is −k (negative of the rate constant).
(iii) Unit of rate constant
For a zero-order reaction:
Rate = k
Rate has units of concentration/time.
If concentration is in mol L−1 and time in seconds:
Unit of k = mol L−1s−1
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संबंधित प्रश्न
Write molecularity of the following reaction:
2NO(g)+O2(g)→2NO2(g)
For a reaction: 
Rate = k
(i) Write the order and molecularity of this reaction.
(ii) Write the unit of k.
A reaction is first order in A and second order in B. Write the differential rate equation.
In a reaction between A and B, the initial rate of reaction (r0) was measured for different initial concentrations of A and B as given below:
| A/mol L−1 | 0.20 | 0.20 | 0.40 |
| B/mol L−1 | 0.30 | 0.10 | 0.05 |
| r0/mol L−1 s−1 | 5.07 × 10−5 | 5.07 × 10−5 | 1.43 × 10−4 |
What is the order of the reaction with respect to A and B?
For which type of reactions, order and molecularity have the same value?
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Assertion: Order and molecularity are same.
Reason: Order is determined experimentally and molecularity is the sum of the stoichiometric coefficient of rate determining elementary step.
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