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Find the Total Percentage of Oxygen in Magnesium Nitrate Crystal Mg(No3)2.6h2o.

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प्रश्न

Find the total percentage of oxygen in magnesium nitrate crystal Mg(NO3)2.6H2O.
[H = 1, N = 14, O = 16, Mg = 24]

योग
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उत्तर

Molecular mass of Mg (NO3)2.6H2O is = 256
Now, 256 parts by weight of crystal contains 192 parts by weight of oxygen.
So 100 parts by weight will contain = 192 x 100/256 = 75‰
Hence, total percentage of oxygen in magnesium nitrate crystal Mg(NO3)2.6H2O is 75‰

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अध्याय 5: Mole Concept and Stoichiometry - Questions from ICSE Examinations [पृष्ठ ११३]

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फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 5 Mole Concept and Stoichiometry
Questions from ICSE Examinations | Q 1996. 3. | पृष्ठ ११३

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