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Find the volume of the largest cylinder that can be inscribed in a sphere of radius ‘r’ cm.

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प्रश्न

Find the volume of the largest cylinder that can be inscribed in a sphere of radius ‘r’ cm.

योग
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उत्तर

Let R be the radius and h be the height of the cylinder which is inscribed in a sphere of radius r cm.

Then from the figure,

`"R"^2 + (h/2)^2` = r2

∴ R2  = `r^2 - h^2/(4)`   ...(1)

Let V be the volume of the cylinder.
Then V = πR2h

= `pi(r^2 - h^2/(4))h`   ...[By (1)]

= `pi(r^2 - h^3/(4))`

∴ `"dV"/"dh" = pid/"dh"(r^2h - h^3/(4))`

= `pi(r^2 xx 1 - 1/4 xx 3h^2)`

= `pi(r^2 - 3/4h^2)`
and
`(d^2V)/("dh"^2) = pid/"dh"(r^2 - 3/4h^2)`

= `pi(0 - 3/4 xx 2h)`

= `-(3)/(2)pih`

Now, `"dV"/"dh" = 0  "gives", pi(r^2 - 3/4h^2)` = 0

∴ `r^2 - 3/4h^2` = 0

∴ `(3)/(4)h^2` = r

∴ h2 = `(4r^2)/(3)`

∴ h = `(2r)/sqrt(3)`          ...[∵ h > 0]
and
`((d^2V)/(dh^2))_("at"  h = (2r)/sqrt(3)`

= `-(3)/(2)pi xx (2r)/sqrt(3) < 0`

∴ V is maximum at h = `(2r)/sqrt(3)`

If h = `(2r)/sqrt(3)`, then from (1)

R2 = `r^2 - (1)/(4) xx (4r^2)/(3) = (2r^2)/(3)`

∴ volumeof the largest cylinder

= `pi xx (2r^2)/(3) xx (2r)/sqrt(3) = (4pir^3)/(3sqrt(3)`cu cm.

Hence, the volume of the largest cylinder inscribed in a sphere of radius 'r' cm = `(4pir^3)/(3sqrt(3)`cu cm.

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अध्याय 2: Applications of Derivatives - Exercise 2.4 [पृष्ठ ९०]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
अध्याय 2 Applications of Derivatives
Exercise 2.4 | Q 22 | पृष्ठ ९०

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