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प्रश्न
Find the value of the trigonometric function sin `(-11pi)/3`.
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उत्तर
`-(11pi)/3 + 4 pi`
= `-(11pi)/3 + (12pi)/3 = pi/3`
`sin (-(11pi)/3)`
= `sin(pi/3)`
`sin (pi/3) = sqrt3/2`
`sin (-(11pi)/3) = sqrt3/2`
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