Advertisements
Advertisements
प्रश्न
Find the value of the angle in the given figure:

Advertisements
उत्तर
In the figure,
∠A + ∠B + ∠C = 180° .....(Sum of angles of a triangle)
⇒ x° + 2x° + 2x° = 180°
⇒ 5x° = 180°
⇒ x° = `(180°)/5=36°`
∴ ∠A = x° = 36°
∠B = 2x° = 2 × 36° = 72°
and ∠C = 2x° = 2 × 36° = 72°
APPEARS IN
संबंधित प्रश्न
Can a triangle have two obtuse angles? Justify your answer in case.
Compute the value of x in the following figure:

Is the following statement true and false :
A triangle can have two right angles.
In the given figure, AE bisects ∠CAD and ∠B= ∠C. Prove that AE || BC.

In ΔABC, ∠B = ∠C and ray AX bisects the exterior angle ∠DAC. If ∠DAX = 70°, then ∠ACB =
In ΔRST (See figure), what is the value of x?

Find the unknown marked angles in the given figure:

In the following, find the marked unknown angle:

In ∆ABC, C = 56° C = 56° ∠B = ∠C and ∠A = 100° ; find ∠B.
Can we have two acute angles whose sum is a right angle? Why or why not?
