Advertisements
Advertisements
प्रश्न
Find the sum of: x2 + x – 2, 2x – 3x2 + 5 and 2x2 – 5x + 7
Advertisements
उत्तर
x2 + x – 2, 2x – 3x2 + 5 and 2x2 – 5x + 7
= x2 + x – 2 + 2x – 3x2 + 5 + 2x2 – 5x + 7
= x2 - 3x2 + 2x2 + x + 2x - 5x - 2 + 5 + 7
= 3x2 - 3x2 + 3x - 5x - 2 + 12
= 0 - 2x + 10
= - 2x + 10
APPEARS IN
संबंधित प्रश्न
Identify the numerical coefficient of term (other than constant) in the following expression:
5 − 3t2
Fill in the blank:
6xy2 – 9xy2 = ______
Add : a + b and 2a + 3b
Simplify: - 2x (x + y) + x2
Simplify: {9 – (4p – 6q)} – {3q – (5p – 10)}
Find the missing term
2y(5x2y – ___ + 3 ___ ) = 10x2y2 – 2xy + 6y3
Some of the factors of `n^2/2 + n/2` are `1/2, n` and (n + 1).
Write the coefficient of x2 in the following:
x2 – x + 4
Write the coefficient of x2 in the following:
x3 – 2x2 + 3x + 1
Find the numerical coefficient of the terms:
10xyz, –7xy2z, –9xyz, 2xy2z, 2x2y2z2
