Advertisements
Advertisements
प्रश्न
Find the sum of: x2 + x – 2, 2x – 3x2 + 5 and 2x2 – 5x + 7
Advertisements
उत्तर
x2 + x – 2, 2x – 3x2 + 5 and 2x2 – 5x + 7
= x2 + x – 2 + 2x – 3x2 + 5 + 2x2 – 5x + 7
= x2 - 3x2 + 2x2 + x + 2x - 5x - 2 + 5 + 7
= 3x2 - 3x2 + 3x - 5x - 2 + 12
= 0 - 2x + 10
= - 2x + 10
APPEARS IN
संबंधित प्रश्न
Constant is only 8 other is variable 3x2 × 5x
Fill in the blank:
4a + 3b – 7a + 4b = _____
Find the sum of: 3x + 8y + 7z, 6y + 4z- 2x and 3y – 4x + 6z
Find the sum of: 4x3 + 2x2 – x + 1, 2x3 – 5x2 – 3x + 6, x2 + 8 and 5x3 – 7x
The two adjacent sides of a rectangle are 6a + 96 and 8a- 46. Find its, perimeter.
Enclose the given term in bracket as required:
x – y – z = x - {…….)
Simplify: `"b"("2b" - 1/"b") - "2b"("b" - 1/"b")`
Find the numerical co-efficient of the following term:
121bc
Number of factors of (a + b)2 is ______.
Write the coefficient of x2 in the following:
x3 – 2x2 + 3x + 1
