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प्रश्न
Find the sum of: x2 + x – 2, 2x – 3x2 + 5 and 2x2 – 5x + 7
बेरीज
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उत्तर
x2 + x – 2, 2x – 3x2 + 5 and 2x2 – 5x + 7
= x2 + x – 2 + 2x – 3x2 + 5 + 2x2 – 5x + 7
= x2 - 3x2 + 2x2 + x + 2x - 5x - 2 + 5 + 7
= 3x2 - 3x2 + 3x - 5x - 2 + 12
= 0 - 2x + 10
= - 2x + 10
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