Advertisements
Advertisements
प्रश्न
Factorise the following expression.
a2b + a2c + ab + ac + b2c + c2b
बेरीज
Advertisements
उत्तर
We have,
a2b + a2c + ab + ac + b2c + c2b
= (a2b + ab + b2c) + (a2c + ac + c2b)
= b(a2 + a + bc) + c(a2 + a + bc)
= (a2 + a + bc)(b + c)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
APPEARS IN
संबंधित प्रश्न
Fill in the blank:
8x - 5x = ________
Fill in the blank:
6xy2 + 9xy2 = _____.
Find the sum of: x2 + x – 2, 2x – 3x2 + 5 and 2x2 – 5x + 7
Find the sum of: -2a and +5
The two adjacent sides of a rectangle are 6a + 96 and 8a- 46. Find its, perimeter.
Enclose the given term in bracket as required:
4a – 9 + 2b – 6 = 4a – (……..)
Simplify: 2x – (x + 2y- z)
An irreducible factor of 24x2y2 is ______.
Some of the factors of `n^2/2 + n/2` are `1/2, n` and (n + 1).
Write the coefficient of x2 in the following:
x3 – 2x2 + 3x + 1
