Advertisements
Advertisements
प्रश्न
Factorise the following expression.
ax2y – bxyz – ax2z + bxy2
Advertisements
उत्तर
We have,
ax2y – bxyz – ax2z + bxy2
= x(axy – byz – axz + by2)
= x(axy – axz – byz + by2)
= x[ax(y – z) + by(–z + y)]
= x[(ax + by)(y – z)]
APPEARS IN
संबंधित प्रश्न
In -5x3y2z4 ; write the coefficient of -xy2. Also, write the degree of the given algebraic expression.
Find the sum of: 3x + 8y + 7z, 6y + 4z- 2x and 3y – 4x + 6z
Find the sum of: abc + 2ba + 3ac + 4ca – 4ab + 2bca + 2ab – 3abc – 6ac
Simplify: 5 x (2x + 3y) – 2x (x – 9y)
Simplify: 6a – 3 (a + b – 2)
Find the numerical co-efficient of the following term:
2ab
Common factor of 17abc, 34ab2, 51a2b is ______.
Factorised form of p2 – 17p – 38 is ______.
The factors of a2 – 2ab + b2 are (a + b) and (a + b).
Write the greatest common factor in the following terms.
63p2a2r2s, – 9pq2r2s2, 15p2qr2s2, – 60p2a2rs2
