Advertisements
Advertisements
प्रश्न
Find the sum of: 4x3 + 2x2 – x + 1, 2x3 – 5x2 – 3x + 6, x2 + 8 and 5x3 – 7x
Advertisements
उत्तर
4x3 + 2x2 – x + 1, 2x3 – 5x2 – 3x + 6, x2 + 8 and 5x3 – 7x
4x3 + 2x2 – x + 1 + 2x3 – 5x2 – 3x + 6 + x2 + 8 + 5x3 – 7x
= 4x3 + 2x3 + 5x3 + 2x2 - 5x2 + x2 - x - 3x - 7x + 1 + 6 + 8
= 11x3 + 3x2 - 5x2 - 11x + 15
= 11x3 - 2x2 - 11x + 15
APPEARS IN
संबंधित प्रश्न
Identify the numerical coefficient of term (other than constant) in the following expression:
5 − 3t2
Constant is only 8 other is variable a3 – 3ab2 x c
Simplify: 7n2 – 9n2 + 3n2
Add : 2x + y and 3x – 4y
Enclose the given term in bracket as required:
x – y – z = x - {…….)
Simplify: `"x" - ("3y" - bar"4x - 3x" + 2z - bar"5y - 7x")`
Find the numerical co-efficient of the following term:
– x
The factors of x2 – 4 are ______.
Factorise the following expression.
2ax2 + 4axy + 3bx2 + 2ay2 + 6bxy + 3by2
Write the coefficient of x2 in the following:
1 + 2x + 3x2 + 4x3
