Advertisements
Advertisements
प्रश्न
Find the middle term of the AP. 95, 86, 77, ........, – 247.
Advertisements
उत्तर
Given A.P. is 95, 86, 77, ....., – 247
Here, a = 95, d = 86 – 95 = – 9
Let the A.P. has n terms.
Then, an = a + (n – 1)d
⇒ – 247 = 95 + (n – 1) (– 9)
⇒ – 247 = 95 – 9n + 9
⇒ – 247 = 104 – 9n
⇒ 9n = 104 + 247
⇒ 9n = 351
⇒ n = 39
Thus, the given A.P. has 39 terms.
Now, Middle term = `[1/2 (39 + 1)]^(th)` term
= `[1/2 (40)]^(th)` term
= 20th term
a20 = a + 19d
= 95 + 19 (– 9)
= 95 – 171
= – 76
As a result, the specified A.P.'s middle term is – 76.
APPEARS IN
संबंधित प्रश्न
Check whether -150 is a term of the A.P. 11, 8, 5, 2, ....
Determine the A.P. whose 3rd term is 16 and the 7th term exceeds the 5th term by 12.
In an AP given a3 = 15, S10 = 125, find d and a10.
Find the sum 25 + 28 + 31 + ….. + 100
Which term of the AP 21, 18, 15, ... is –81?
Divide 24 in three parts such that they are in AP and their product is 440.
The first term of an AP is p and its common difference is q. Find its 10th term.
If `4/5`, a, 2 are in AP, find the value of a.
How many terms of the A.P. 21, 18, 15, ... must be added to get the sum 0?
In an A.P. 17th term is 7 more than its 10th term. Find the common difference.
For an given A.P., t7 = 4, d = −4, then a = ______.
If Sn denotes the sum of first n terms of an A.P., prove that S12 = 3(S8 − S4).
Mark the correct alternative in each of the following:
If 7th and 13th terms of an A.P. be 34 and 64 respectively, then its 18th term is
Q.2
Obtain the sum of the first 56 terms of an A.P. whose 18th and 39th terms are 52 and 148 respectively.
Find S10 if a = 6 and d = 3.
If the sum of first n terms of an AP is An + Bn² where A and B are constants. The common difference of AP will be ______.
If the sum of three numbers in an A.P. is 9 and their product is 24, then numbers are ______.
An AP consists of 37 terms. The sum of the three middle most terms is 225 and the sum of the last three is 429. Find the AP.
Find the sum of first 20 terms of an A.P. whose nth term is given as an = 5 – 2n.
