मराठी
महाराष्ट्र राज्य शिक्षण मंडळएस.एस.सी (इंग्रजी माध्यम) इयत्ता १० वी

Find the middle term of the AP. 95, 86, 77, ........, – 247. - Algebra Mathematics 1

Advertisements
Advertisements

प्रश्न

Find the middle term of the AP. 95, 86, 77, ........, – 247.

बेरीज
Advertisements

उत्तर

Given A.P. is 95, 86, 77, ....., – 247

Here, a = 95, d = 86 – 95 = – 9

Let the A.P. has n terms.

Then, an = a + (n – 1)d

⇒ – 247 = 95 + (n – 1) (– 9)

⇒ – 247 = 95 – 9n + 9

⇒ – 247 = 104 – 9n

⇒ 9n = 104 + 247

⇒ 9n = 351

⇒ n = 39

Thus, the given A.P. has 39 terms.

Now, Middle term = `[1/2 (39 + 1)]^(th)` term

= `[1/2 (40)]^(th)` term

= 20th term

a20 = a + 19d

= 95 + 19 (– 9)

= 95 – 171

= – 76

As a result, the specified A.P.'s middle term is – 76.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2025-2026 (March) Model set 3 by shaalaa.com

संबंधित प्रश्‍न

Find the 9th term from the end (towards the first term) of the A.P. 5, 9, 13, ...., 185


If the mth term of an A.P. is 1/n and the nth term is 1/m, show that the sum of mn terms is (mn + 1)


Find the sum of the following APs.

−37, −33, −29, …, to 12 terms.


In an AP given a = 8, an = 62, Sn = 210, find n and d.


In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato and other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line.

A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?

[Hint: to pick up the first potato and the second potato, the total distance (in metres) run by a competitor is 2 × 5 + 2 ×(5 + 3)]


How many two-digit number are divisible by 6?


Show that `(a-b)^2 , (a^2 + b^2 ) and ( a^2+ b^2) ` are in AP.


Draw a triangle PQR in which QR = 6 cm, PQ = 5 cm and times the corresponding sides of ΔPQR?


The first term of an A. P. is 5 and the common difference is 4. Complete the following activity and find the sum of the first 12 terms of the A. P.

a = 5, d = 4, s12 = ?
`s_n = n/2 [ square ]`
`s_12 = 12/2 [10 +square]`
         `= 6 × square  `
         ` =square`


Simplify `sqrt(50)`


The sum of first seven terms of an A.P. is 182. If its 4th and the 17th terms are in the ratio 1 : 5, find the A.P.


Let there be an A.P. with first term 'a', common difference 'd'. If an denotes in nth term and Sn the sum of first n terms, find.

\[k, \text{ if }  S_n = 3 n^2 + 5n \text{ and }  a_k = 164\]

 


The 9th term of an A.P. is 449 and 449th term is 9. The term which is equal to zero is


If \[\frac{5 + 9 + 13 + . . . \text{ to n terms} }{7 + 9 + 11 + . . . \text{ to (n + 1) terms}} = \frac{17}{16},\] then n =

 


Two cars start together in the same direction from the same place. The first car goes at uniform speed of 10 km h–1. The second car goes at a speed of 8 km h1 in the first hour and thereafter increasing the speed by 0.5 km h1 each succeeding hour. After how many hours will the two cars meet?


Q.4


The sum of all odd integers between 2 and 100 divisible by 3 is ______.


Find the sum of first 'n' even natural numbers.


Which term of the Arithmetic Progression (A.P.) 15, 30, 45, 60...... is 300?

Hence find the sum of all the terms of the Arithmetic Progression (A.P.)


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×