Advertisements
Advertisements
प्रश्न
Find the mean proportional of the following:
17.5, 0.007
Advertisements
उत्तर
Let x be the mean proportional between 17.5 and 0.007.
Then,
17.5 : x :: x : 0.007
⇒ 17.5, x and 0.007 are in continued proportion.
⇒ `17.5/x = x/0.007`
⇒ x × x = 17.5 × 0.007
⇒ x2 = 0.1225
⇒ x = `sqrt0.1225`
⇒ x = 0.35
APPEARS IN
संबंधित प्रश्न
Find two numbers such that the mean proportional between them is 14 and third proportional to them is 112.
Find the fourth proportion to the following :
(x2 - y2),(x3 + y3)anc(x3 - xy2 + x2y- y3)
If ( a+c) : b = 5 : 1 and (bc + cd) : bd = 5 : 1, then prove that a : b = c : d
Using the properties of proportion, solve for x, given. `(x^4 + 1)/(2x^2) = (17)/(8)`.
Find the third proportional to Rs. 3, Rs. 12
Find the mean proportion of: `(1)/(12) and (1)/(75)`
A car travels 90 km in 3 hours with constant speed. It will travel 140 km in 5 hours at the same speed
Which of the following ratios are in proportion?
Determine if the following ratios form a proportion. Also, write the middle terms and extreme terms where the ratios form a proportion.
39 litres : 65 litres and 6 bottles : 10 bottles
If x, y and z are in continued proportion, Prove that:
`x/(y^2.z^2) + y/(z^2.x^2) + z/(x^2.y^2) = 1/x^3 + 1/y^3 + 1/z^3`
