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प्रश्न
Find the mean proportional of the following:
`1/16, 4/25`
योग
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उत्तर
Let x be the mean proportional between `1/16 and 4/25`.
Then,
`1/16` : x :: x, `4/25`
⇒ `(1/16)/x = x/(4/25)`
⇒ x2 = `1/16 xx 4/25`
⇒ x = ±`sqrt(1/6 xx 4/25)`
⇒ x = ±`sqrt(4/400)`
⇒ x = ±`sqrt(1/100)`
⇒ x = ±`1/10`
As `-1/10` does not lie between two positive numbers `1/16 and 4/25`.
∴ x = `1/10`
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Ratio and proportion - Exercise 7B [पृष्ठ १२५]
