Advertisements
Advertisements
प्रश्न
Find the magnitude of angle A, if tan A - 2 cos A tan A + 2 cos A - 1 = 0
Advertisements
उत्तर
tan A – 2 cos A tan A + 2 cos A – 1 = 0
tan A – 2 cos A tan A = 1 – 2 cos A
tan A ( 1 – 2 cos A ) – (1 – 2 cos A )= 0
(1 – 2 cos A) (tan A – 1) = 0
1 – 2 cos A = 0 and tan A – 1 = 0
cos A = `(1)/(2)` and tan A = 1
A = 60° and A = 45°
संबंधित प्रश्न
Use the given figure to find:
(i) tan θ°
(ii) θ°
(iii) sin2θ° - cos2θ°
(iv) Use sin θ° to find the value of x.
If 4 cos2 x = 3 and x is an acute angle;
find the value of :
(i) x
(ii) cos2 x + cot2 x
(iii) cos 3x (iv) sin 2x
Find the value of 'A', if 2 cos A = 1
Evaluate the following: `((sin3θ - 2sin4θ))/((cos3θ - 2cos4θ))` when 2θ = 30°
In the given figure, PQ = 6 cm, RQ = x cm and RP = 10 cm, find
a. cosθ
b. sin2θ- cos2θ
c. Use tanθ to find the value of RQ
Find the value of 'x' in each of the following:
Find the value of 'y' if `sqrt(3)` = 1.723.
Given your answer correct to 2 decimal places.
Evaluate the following: `(cos34° cos35°)/(sin57° sin56°)`
Evaluate the following: `(sin36°)/(cos54°) + (sec31°)/("cosec"59°)`
Express each of the following in terms of trigonometric ratios of angles between 0° and 45°: cos72° - cos88°
