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प्रश्न
Find the fundamental, first overtone, and second overtone frequencies of a pipe, open at both the ends, of length 25 cm if the speed of sound in air is 330 m/s.
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उत्तर
Data: Open pipe, L = 25 cm = 0.25 m, v = 330 m/s The fundamental frequency of an open pipe ignoring end correction,
nO = `"v"/λ="v"/(2"L")`
∴ nO = `330/(2xx0.25)` = 660 Hz
Since all harmonics are present as overtones, the first overtone is,
n1 = 2nO = 2 × 660 = 1320 Hz
The second overtone is
n2 = 3n = 3 × 660 = 1980 Hz
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Answer in brief:
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