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A standing wave is produced in a tube open at both ends. The fundamental frequency is 300 Hz. What is the length of the tube? (speed of the sound = 340 m s-1).

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प्रश्न

A standing wave is produced in a tube open at both ends. The fundamental frequency is 300 Hz. What is the length of the tube? (speed of the sound = 340 m s-1).

योग
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उत्तर

Data: For the tube open at both the ends,

n = 300 Hz and v = 340 m s-1 Ignoring end correction, the fundamental frequency of the tube is

n = `"v"/("2L")`

∴ L = `"v"/(2"n")=340/(2xx300)` = 0.566 m

The length of the tube open at both the ends is 0.5667 m.

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अध्याय 6: Superposition of Waves - Exercises [पृष्ठ १५७]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 6 Superposition of Waves
Exercises | Q 16. | पृष्ठ १५७

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