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Show that the distance between two successive nodes or antinodes is λ/2.

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प्रश्न

Show that the distance between two successive nodes or antinodes is λ/2.

व्युत्पत्ति
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उत्तर

Condition for node:

Nodes are the points of minimum displacement. This is possible if the amplitude is minimum (zero), i.e.,

`2a cos (2 pi x)/lambda = 0`, or

`cos (2 pi x)/lambda = 0`, or

`(2 pi x)/lambda = pi/2, (3 pi)/2, (5 pi)/2, ....`

∴ `x = lambda/4, (3 lambda)/4, (5 lambda)/4, ....`

i.e., `x = (2 p - 1) lambda/4` where p = 1, 2, 3, ....

The distance between two successive nodes is `lambda/2`.

Condition for antinode:

Antinodes are the points of maximum displacement

i.e., A = ± 2a

∴ `2a cos  (2 pi x)/lambda = +-2a`

or, `cos  (2 pi x)/lambda = +-1`

∴ `(2 pi x)/lambda = 0, pi, 2pi, 3pi, ....`

or, `x = 0, lambda/2, lambda,(3 lambda)/2, ....`

i.e., `x = (lambda p)/2` where p = 0, 1, 2, 3, ....

The distance between two successive antinodes is `lambda/2`. Nodes and antinodes are formed 2 alternately. Therefore, the distance between a node and an adjacent antinode is `lambda/4`.

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अध्याय 6: Superposition of Waves - Long Answer

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एससीईआरटी महाराष्ट्र Physics [English] 12 Standard HSC
अध्याय 6 Superposition of Waves
Long Answer | Q 1. iv.

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