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Answer in brief: What are harmonics and overtones? - Physics

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प्रश्न

Answer in brief:

What are harmonics and overtones?

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उत्तर

A stationary wave is formed in a bounded condition, with the boundary being either rigid support or a free end. The boundary conditions restrict the possible stationary waves and allow only a discrete set of frequencies.

The fundamental frequency of vibration is the lowest allowed frequency, n1. Harmonics are integral multiples of the fundamental frequency. The harmonics may or may not be present in the sound so produced. The first harmonic is defined as the fundamental frequency. The second harmonic is 2n1, which is twice the fundamental, and the third harmonic is 3n1, and so on. 

Consider a vibrating string. The modes of vibration are all multiples of the fundamental and are related to the string length and wave velocity. Higher frequencies are found via the relationship fn= nf1, wavelength = `2"L"/"n"` where L is the string length.

An overtone is a name given to any resonant frequency above the fundamental frequency or fundamental tone. The first permitted frequency over the fundamental is termed the first overtone, the next higher frequency is called the second overtone, and so on. The list of successive overtones for an object is called the overtone series. The first overtone as well as all subsequent overtones in the series may or may not be an integer multiple of the fundamental. Sometimes the relationship is that simple, and other times it is more complex, depending on the properties and geometry of the vibrating object.

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Harmonics and Overtones
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अध्याय 6: Superposition of Waves - Exercises [पृष्ठ १५६]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 6 Superposition of Waves
Exercises | Q 2.3 | पृष्ठ १५६

संबंधित प्रश्न

A pipe closed at one end can produce overtones at frequencies 640 Hz, 896 Hz, and 1152 Hz. Calculate the fundamental frequency.


A pipe open at both the ends has a fundamental frequency of 600 Hz. The first overtone of a pipe closed at one end has the same frequency as the first overtone of the open pipe. How long are the two pipes?

(Given: v = 330 m/s)


A string 1m long is fixed at one end. The other end is moved up and down with frequency of 15 Hz. Due to this, a stationary wave with four complete loops gets produced on the string. Find the speed of the progressive wave which produces the stationary wave.
[Hint: Remember that the moving end is an antinode.]


Two identical strings of length I and 2I vibrate with fundamental frequencies N Hz and 1.5 N Hz, respectively. The ratio of tensions for smaller length to large length is ____________.


Two open pipes of different lengths and same diameter in which the air column vibrates with fundamental frequencies 'n1', and 'n2' respectively. When both pipes are joined to form a single pipe, its fundamental frequency will be ______.


A tube closed at one end and containing air produces fundamental note of frequency 256 Hz. If the tube is open at both ends, the fundamental frequency will be ____________.


An organ pipe has a fundamental frequency of 120 Hz. Its fourth overtone is 600 Hz. Find the type of the pipe.


An air column, closed at one end and open at the other resonates with a tuning fork of frequency v, when its length is 45 cm, 99 cm and at two other lengths in between these values. The wavelength of sound in air column is ____________.


A pipe open at both ends and a pipe closed at one end have same length. The ratio of frequencies of their pth overtone is ______.


Length of an organ pipe open at both ends is 34 cm. If velocity of sound is 340 m is, then the frequency of 2nd overtone is ______.


A stretched uniform wire of length L under tension T is vibrating with frequency 'n' . A closed pipe of same length is also vibrating with same fundamental frequency 'n'. If T is increased by 16 N, it is in resonance with 2nd harmonic of same closed pipe. The initial tension in the wire is ______.


A pipe of length 85 cm is closed from one end. Find the number of possible natural oscillations of air colunm in the pipe whose frequencies lie below 1250 Hz. The velocity of sound in air is 340 m/s.


'n' number of waves are produced on a string in 0.5 seconds. Now the tension in a string is doubled (Keeping radius constant). The number of waves produced in 0.5 seconds for the same harmonic will be ______


The equation of simple harmonic wave is given as y = 5sin `pi/2(100t - x)`, where 'x' and 'y' are in metre and time in second. The period of the wave is ______ 


A pipe closed at one end produces a fundamental note of frequency 'v'. It is cut into two pipes of equal length. The fundamental frequencies produced in the two pipes are ______.


If the length and diameter of a wire are decreased, then for the same tension the natural frequency of stretched wire will ______.


An organ pipe P1 closed at one end vibrating in its first overtone and another pipe P2 open at both ends vibrating in third overtone are in resonance with a given tuning fork. The ratio of the length of P1 to that of P2 is ______.


The closed and open organ pipes have same length. When they are vibrating simultaneously in first overtone, produce three beats. The length of open pipe is made `1/3` rd and closed pipe is made three times the original, the number of beats produced will be ______.


A pipe Pc closed at one end and point Po open at both ends are vibrating in the second overtone. They are in resonance with a given tuning fork. The ratio of the length of pipe Pc to that of pipe, Po is ______.

(Neglect end correction).


An open pipe is in resonance in its 2nd harmonic with tuning fork of frequency f1. Now, it is closed at one end. If the frequency of the tuning fork is increased slowly from f1, then again a resonance is obtained with a frequency f2. If in this case the pipe vibrates nth harmonic, then ______.


An organ pipe closed at one end resonates with a tuning fork of frequencies 180 Hz and 300 Hz. It will also resonate with tuning fork of frequency ______.


Two organ pipes closed at one end have the same diameters but different lengths. Show that the end correction at each end is e = `(n_1l_1 - n_2l_2)/(n_2 - n_1)`, where the symbols have their usual meanings. Take `γ = 5/3`.


Prove that for pipe closed at one end, the end correction is `e = (n_2l_2-n_1l_1)/(n_1-n_2)`


A sonometer wire is subjected to a certain tension. If the tension is increased four times and the length of wire is reduced to half the original value, how is frequency of vibrations altered?


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