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Find the equation of the line of regression of Y on X for the following data: n = 8, ∑(xi-x¯).(yi-y¯)=120,x¯=20,y¯=36,σx=2,σy=3

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प्रश्न

Find the equation of the line of regression of Y on X for the following data:

n = 8, `sum(x_i - barx).(y_i - bary) = 120, barx = 20, bary = 36, sigma_x = 2, sigma_y = 3`

योग
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उत्तर

Given, n = 8, `sum(x_i - barx)(y_i - bary)` = 120,

`barx` = 20, `bary` = 36, `sigma_x` = 2, `sigma_y` = 3

∴ Var (X) = `sigma_"X"^2` = 4

Since Var (X) = `(sum (x_i - bar x))/"n"`,

4 = `(sum (x_i - bar x))^2/8`

∴ `sum (x_i - bar x)^2` = 32

Now, `"b"_"YX" = (sum ("x"_"i" - bar"x")("y"_"i" - bar"y"))/(sum("x"_"i" - bar"x")^2) = 120/32` = 3.75

∴ The regression equation of Y on X is

`("Y" - bar y) = "b"_"YX" ("X" - bar x)`

∴ (Y – 36) = 3.75 (X – 20)

∴ Y – 36 = 3.75X – 75

∴ Y = 3.75X – 75 + 36

∴ Y = 3.75 X – 39

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अध्याय 3: Linear Regression - Miscellaneous Exercise 3 [पृष्ठ ५४]

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बालभारती Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 3 Linear Regression
Miscellaneous Exercise 3 | Q 4.09 | पृष्ठ ५४

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Solution: Line of regression of Y on X is

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∴ Y − 12 = `0.6 xx 4/square ("X" - 10)`

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∴ Y = `square`


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