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प्रश्न
Find the equation for the ellipse that satisfies the given conditions:
Length of major axis 26, foci (±5, 0)
योग
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उत्तर
Length of major axis = 26; foci = (±5, 0).
Since the foci are on the x-axis, the major axis is along the x-axis.
Therefore, the equation of the ellipse will be of the form `x^2/a^2 + y^2/b^2 = 1` where a is the semi-major axis.
Accordingly, 2a = 26 = a = 13 and c = 5.
It is known that a2 = b2 + c2
∴ 132 = b2 + 52
= 169 = b2 + 25
= b2 = 169 - 25
= b = `sqrt144` = 12
Thus, the equation of the ellipse is `x^2/13^2 + y^2/12^2 = 1` or `x^2/169 + y^2/144 = 1`.
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