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Find the equation for the ellipse that satisfies the given conditions: Length of major axis 26, foci (±5, 0) - Mathematics

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प्रश्न

Find the equation for the ellipse that satisfies the given conditions:

Length of major axis 26, foci (±5, 0)

योग
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उत्तर

Length of major axis = 26; foci = (±5, 0).

Since the foci are on the x-axis, the major axis is along the x-axis.

Therefore, the equation of the ellipse will be of the form `x^2/a^2 + y^2/b^2 = 1` where a is the semi-major axis.

Accordingly, 2a = 26 = a = 13 and c = 5.

It is known that a2 = b2 + c2

∴ 132 = b2 + 52

= 169 = b2 + 25

= b2 = 169 - 25

= b = `sqrt144` = 12

Thus, the equation of the ellipse is  `x^2/13^2 + y^2/12^2 = 1` or  `x^2/169 + y^2/144 = 1`.

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अध्याय 10: Conic Sections - EXERCISE 10.3 [पृष्ठ १९५]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 10 Conic Sections
EXERCISE 10.3 | Q 15. | पृष्ठ १९५
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