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Find the absolute maximum value and the absolute minimum value of the following function in the given interval: f (x) = (x −1)2 + 3, x ∈[−3,1]

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प्रश्न

Find the absolute maximum value and the absolute minimum value of the following function in the given interval:

f (x) = (x −1)2 + 3, x ∈[−3, 1]

योग
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उत्तर

Given function f(x) = (x - 1)2 + 3 in the interval [-3, 1]

∴ f'(x) = 2(x - 1)

For critical points, let f' (x) = 0

If f'(x) = 0, then 2(x - 1) = 0,

⇒ x = 1 ∈ [-3, 1]

At, x = 1 f(1) = (1 - 1)2 + 3

= 0 + 3

= 3

At, x = -3 f(-3)

= (-3, -1)2 + 3

= 16 + 3 = 19

∴ Absolute maximum value of f(x) 19 at x = -3

Absolute minimum value of f(x) = 3 at x = 1.

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अध्याय 6: Application of Derivatives - Exercise 6.5 [पृष्ठ २३२]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.5 | Q 5.4 | पृष्ठ २३२

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