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Find equation of the line passing through the point (2, 2) and cutting off intercepts on the axes whose sum is 9. - Mathematics

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प्रश्न

Find equation of the line passing through the point (2, 2) and cutting off intercepts on the axes whose sum is 9.

योग
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उत्तर

Let a and b be the intercepts made on the axes by the line passing through P(2, 2).

equation of line in intercept form

`"x"/"a" + "y"/"b" = 1` 

This line passes through P(2, 2).

∴ `2/"a" + 2/"b" = 1` ..........(i)

It is given that the sum of the segments is 9.

∴ a + b = 9

b = 9 – a

Putting the value of b in (i),

`2/"a" + 2/(9 -"a") = 1`

or 2(9 – a) + 2a = a (9 – a)

18 – 2a + 2a = 9a – a2

or a2 – 9a + 18 = 0

or (a – 6)(a – 3) = 0

a = 6, 3

b = 3, 6

When a = 6 and b = 3, then the required equation of the line is

`"x"/6 + "y"/3  = 1`

or 3x + 6y = 18

or x + 2y = 6

When a = 3 and b = 6, then the required equation of the line is,

`"x"/3 + "y"/6 = 1`

2x + y - 6 = 0

or x + 2y - 6 = 0

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अध्याय 9: Straight Lines - EXERCISE 9.2 [पृष्ठ १६४]

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एनसीईआरटी Mathematics [English] Class 11
अध्याय 9 Straight Lines
EXERCISE 9.2 | Q 12. | पृष्ठ १६४

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