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Find the Equation of a Line for P = 8, α = 300°. - Mathematics

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प्रश्न

Find the equation of a line for p = 8, α = 300°.

संक्षेप में उत्तर
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उत्तर

 p = 8, α = 300°
So, the equation of the line in normal form is 

\[x\cos {300}^\circ + y\sin {300}^\circ = 8\]

\[ \Rightarrow x\cos\left( {360}^\circ - {60}^\circ \right) + y\sin\left( {360}^\circ - {60}^\circ \right) = 8\]

\[ \Rightarrow x\cos {60}^\circ - y\sin {60}^\circ = 8\]

\[ \Rightarrow \frac{x}{2} - \frac{\sqrt{3}y}{2} = 8\]

\[ \Rightarrow x - \sqrt{3}y = 16\]

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अध्याय 23: The straight lines - Exercise 23.7 [पृष्ठ ५३]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 23 The straight lines
Exercise 23.7 | Q 1.4 | पृष्ठ ५३
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