Question

Find the discriminant of the quadratic equation \[3\sqrt{3} x^2 + 10x + \sqrt{3} = 0\].

Answer 1

Given that quadric equation is \[3\sqrt{3} x^2 + 10x + \sqrt{3} = 0\].

Then, find the value of discrimenant.

Here, `a =3sqrt3 , b = 10 and , c = sqrt 3` 

As we know that discrimenant D = b^2 - 4ac

Putting the value of `a =3sqrt3 , b = 10 and , c = sqrt 3` 

` = (10)^2 - 4 xx 3 sqrt3 xx sqrt3`

= 100 - 36

 = 64

Thus, the value of discrimenant be D = 64 .