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प्रश्न
Find the 8th term from the end of the AP 7, 10, 13, ……, 184.
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उत्तर
Here, a = 7 and d = (10-7) = 3,l = 184 and n = 8th form the end.
Now, nth term from the end = [ l - (n-1) d]
8th term from the end = [184-(8-1) x3]
=[ 184-(7×3)]=(184-21)=163
Hence, the 8th term from the end is 163.
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Q.1
Find the sum of natural numbers between 1 to 140, which are divisible by 4.
Activity: Natural numbers between 1 to 140 divisible by 4 are, 4, 8, 12, 16,......, 136
Here d = 4, therefore this sequence is an A.P.
a = 4, d = 4, tn = 136, Sn = ?
tn = a + (n – 1)d
`square` = 4 + (n – 1) × 4
`square` = (n – 1) × 4
n = `square`
Now,
Sn = `"n"/2["a" + "t"_"n"]`
Sn = 17 × `square`
Sn = `square`
Therefore, the sum of natural numbers between 1 to 140, which are divisible by 4 is `square`.
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