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प्रश्न
Factorize `x^2 - sqrt3x - 6`
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उत्तर
Splitting the middle term,
`= x^2 - 2sqrt3x + sqrt3x - 6` `[∵ -sqrt3 = -2sqrt3 + sqrt3 also -2sqrt3 xx sqrt3 = -6]`
`= x(x - 2sqrt3) sqrt3(x - 2sqrt3)`
`= (x - 2sqrt3)(x + sqrt3)`
`∴ x^2 - sqrt3x - 6 = (x - 2sqrt3)(x + sqrt3)`
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