Advertisements
Advertisements
प्रश्न
Factorize `x^2 - sqrt3x - 6`
Advertisements
उत्तर
Splitting the middle term,
`= x^2 - 2sqrt3x + sqrt3x - 6` `[∵ -sqrt3 = -2sqrt3 + sqrt3 also -2sqrt3 xx sqrt3 = -6]`
`= x(x - 2sqrt3) sqrt3(x - 2sqrt3)`
`= (x - 2sqrt3)(x + sqrt3)`
`∴ x^2 - sqrt3x - 6 = (x - 2sqrt3)(x + sqrt3)`
APPEARS IN
संबंधित प्रश्न
Factorize a2 + 2ab + b2 - c2
Factorize the following expressions:
`x^3/216 - 8y^3`
If x − y = 7 and xy = 9, find the value of x2 + y2
What must be added to the following expression to make it a whole square?
4x2 − 12x + 7
What must be added to the following expression to make it a whole square?
4x2 − 20x + 20
If a2 + b2 + c2 = 250 and ab + bc + ca = 3, find a + b + c.
Divide: - 16ab2c by 6abc
Divide: 9x2 - 24xy + 16y2 by 3x- 4y
Divide: x3 − 6x2 + 11x − 6 by x2 − 4x + 3
How many terms does a trinomial contain?
