Advertisements
Advertisements
प्रश्न
Factorize of the following polynomials:
4x3 + 20x2 + 33x + 18 given that 2x + 3 is a factor.
Advertisements
उत्तर
Let ` f(x) = 4x^3 + 20x^2 + 33x+ 18` be the given polynomial.
Therefore (2x + 3)is a factor of the polynomial f(x).
Now,
`f(x)= 2x^2 (2x + 3)+7x(2x + 3) + 6(2x + 3)`
`=(2x + 3){2x^2 + 4x 3x + 6}`
`= (2x + 3){2x^2 + 4x + 3x + 6}`
` = (2x + 3)(2x + 3)(x + 2)`
Hence (x +2),(2x+3) and (2x + 3 ) are the factors of polynomial f(x).
APPEARS IN
संबंधित प्रश्न
f(x) = 9x3 − 3x2 + x − 5, g(x) = \[x - \frac{2}{3}\]
Find the remainder when x3 + 3x2 + 3x + 1 is divided by \[x - \frac{1}{2}\].
f(x) = x3 − 6x2 + 11x − 6, g(x) = x2 − 3x + 2
x3 + 2x2 − x − 2
y3 − 7y + 6
x3 − 2x2 − x + 2
If x − 3 is a factor of x2 − ax − 15, then a =
If x51 + 51 is divided by x + 1, the remainder is
Factorise the following:
`1/x^2 + 1/y^2 + 2/(xy)`
If (x + 5) and (x – 3) are the factors of ax2 + bx + c, then values of a, b and c are
