Advertisements
Advertisements
प्रश्न
Factorise the following:
a4 – 3a2 + 2
Advertisements
उत्तर
Let a2 = x
a4 – 3a2 + 2 = (a2)2 – 3a2 + 2
= x2 – 3x + 2
Product = 2 and sum = – 3
Split the middle term as – x and – 2x
x² – 3x + 2 = x2 – x – 2x + 2
= x(x – 1) – 2(x – 1)
= (x – 1)(x – 2)
a4 – 3a2 + 2 = (a2 – 1)(a2 – 2) ...[But a2 = x]
= (a + 1)(a – 1)(a2 – 2)
APPEARS IN
संबंधित प्रश्न
Write the coefficient of x2 in the following:
`9-12x +X^3`
Write the coefficient of x2 in the following:
`pi/6x^2- 3x+4`
Identify polynomials in the following:
`p(x)=2/3x^3-7/4x+9`
Verify whether the indicated numbers is zeros of the polynomials corresponding to them in the following case:
\[p(x) = x^3 - 6 x^2 + 11x - 6, x = 1, 2, 3\]
Find the remainder when x3 + 3x2 + 3x + 1 is divided by 5 + 2x .
In the following two polynomials, find the value of a, if x + a is a factor x4 − a2x2 + 3x −a.
Find the values of p and q so that x4 + px3 + 2x3 − 3x + q is divisible by (x2 − 1).
y3 − 7y + 6
Factorise the following:
12x2 + 36x2y + 27y2x2
Factorise the following:
`1/x^2 + 1/y^2 + 2/(xy)`
